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Thread: Math Homework-lamsey I Need You!

  1. #1
    I have a math homework problem. It is as follows:

    A rock is thrown into the air from a hole in the ground. The solution for the time it takes the rock to reach a certain distance is (y= -x^2+10x-16). X is the time and y stands for how high above the ground level the rock is. The questions I have to answer are as follows:

    A) What is the rock's maximum height?
    B ) How much time it took for the rock to reach it's maximum height?
    C) How long does it take for it to hit the ground after it was thrown up?
    D) How far down was the rock initially thrown from?

    This is what I know so far:

    The image is of a parabola, that looks like an upside down U. In order to find the turning point, you would use the formula x= -b/2a. That would give you the maximum time is took the rock to reach its peak height. If you were to substitute that number into the equation (y= -x^2+10x-16), that would give you the time it took to reach its maximum height. From there, you would substitute different numbers for X to get different numbers for Y. Can anyone guide me?? I also believe that the X part of the turning point is 5. Am i right???

    This is one for Lamsey

    Thanks for any help you guys might provide.

  2. Lounge   -   #2
    RGX's Avatar Unstoppable
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    The answer is 42.

  3. Lounge   -   #3
    what is 42???

  4. Lounge   -   #4
    Poster
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    6*9 (base 13) according to my DM tutor
    On a given day or given circumstance, you think you have a limit.
    And you then go for this limit and you touch this limit and you think "Ok, this is the limit".
    As soon as you touch this limit, something happens and you suddenly can go a little bit further.
    With your mind power, your determination, your instinct and the experience as well, you can fly very high.

    - Ayrton Senna, R.I.P.

  5. Lounge   -   #5
    anybody- could ya help

  6. Lounge   -   #6
    Illuminati's Avatar Simple Bystander BT Rep: +7BT Rep +7
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    A) will be where the maximum stationary point is. In other words, it'll be where dy/dx (differential of y in respect to x) will be zero. All you need is the y co-ordinate
    B) will be the same as a, except it'll be the x co-ordinate
    C) will be when y = 0 - Substitute 0 for y and find x for the answer
    D) will be when x = 0 - Find f(x) when x = 0 Find y for the answer

    Can't be bothered working them out but that's what you're supposed to do.

    Co-Ordinate Geometry, Pure 1/2, English A-Level Mathematics

    Technically you could in theory solve it in a mechanics sense as well, but that's for another day


  7. Lounge   -   #7
    anybody???

  8. Lounge   -   #8
    is the x part of the turning point 5?

  9. Lounge   -   #9
    TRshady
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    That is oh so rude ..... completely ignoring the fact othrs have tried to help .. and are probably right .. though I wouldn't have a dandy .. called being tired where we come from.

  10. Lounge   -   #10
    shn's Avatar Ð3ƒμ|\|(7
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    Originally posted by Illuminati@24 March 2004 - 19:14
    A) will be where the maximum stationary point is.  In other words, it'll be where dy/dx (differential of y in respect to x) will be zero.  All you need is the y co-ordinate
    B) will be the same as a, except it'll be the x co-ordinate
    C) will be when y = 0 - Find x for the answer
    D) will be when x = 0 - Find y for the answer

    Can't be bothered working them out but that's what you're supposed to do. 

    Co-Ordinate Geometry, Pure 1/2, English A-Level Mathematics

    Technically you could in theory solve it in a mechanics sense as well, but that's for another day
    WoW

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