todays math fun is brought to you by the letters W T and F

[manker]

sure

OK. It can be proved by simplification.

The first step is multiplying by 8 (2X2X2); cancel out step 7 by removing one of the twos.

Step 5 is also cancelled because you've gotten rid of the divisor of two at the end so you must not add the last three digits a second time.

This means that step seven is gone, step 5 is gone and you're multiplying by 4 in the first instance.

We now have

1 Multiply first 3 digits by 4
2 Add 1
3 Multiply by 250
4 Add last three digits
5 Subtract 250

Still works, right?

Steps 2 and 5 cancel themselves out since adding one before multiplying by 250 has the effect of adding 250 to the figure.

We now have

1 Multiply first 3 numbers by 4
2 Multiply by 250
3 Add last 3 digits


Since 4*250= 1000 we may as well simplify further and get rid of step 2 by making step one the first 3 numbers*1000

Now we're left with

1 Multiply the first 3 numbers by 1000
2 Add last 3 digits.

The above is moving the 3 digit number 3 decimal places to the left and slotting in the last 3 digits.

=> It works for everyone.

Note: It's the same principle for 7 digit numbers, it just cancels down to multiplying by 10000 rather than 1000 in it's simplest form.

[muchspl2]

gold star for showing your work, congratulations you screwed up the bell curve and will make every one else have lower grades.

[Cheese]

I don't have a phone.

[manker]

I don't have a phone.

Don't be sad. It still works for you too. With zeros.

[Yogi]

Thanks!!! :crying:

I finally know my number now...............

Is there a reverse process, where i forget it again???

[(>Zero Cool<)]

OK. It can be proved by simplification.

The first step is multiplying by 8 (2X2X2); cancel out step 7 by removing one of the twos.

Step 5 is also cancelled because you've gotten rid of the divisor of two at the end so you must not add the last three digits a second time.

This means that step seven is gone, step 5 is gone and you're multiplying by 4 in the first instance.

We now have

1 Multiply first 3 digits by 4
2 Add 1
3 Multiply by 250
4 Add last three digits
5 Subtract 250

Still works, right?

Steps 2 and 5 cancel themselves out since adding one before multiplying by 250 has the effect of adding 250 to the figure.

We now have

1 Multiply first 3 numbers by 4
2 Multiply by 250
3 Add last 3 digits


Since 4*250= 1000 we may as well simplify further and get rid of step 2 by making step one the first 3 numbers*1000

Now we're left with

1 Multiply the first 3 numbers by 1000
2 Add last 3 digits.

The above is moving the 3 digit number 3 decimal places to the left and slotting in the last 3 digits.

=> It works for everyone.

Note: It's the same principle for 7 digit numbers, it just cancels down to multiplying by 10000 rather than 1000 in it's simplest form.

slow day at work was it manker?

[manker]

slow day at work was it manker?

You mean that the world doesn't stop for everyone when a hawt logic problem presents itself! Unbelievable!

[(>Zero Cool<)]

You mean that the world doesn't stop for everyone when a hawt logic problem presents itself! Unbelievable!

or :crying:

basically I don't know whether to laugh with you or cry for you on that one

[Gemby!]

21592