Help Me Guess The Jellybeans!

[Infested Cats]

So, I'm sure most (if not all) of you are familiar with those "Guess how many jellybeans there are" contests. Well, I figured I could get some of you to share your educated guesses with me. With this post, I have included pictures of the FACE, SIDE, and BOTTOM of the container. Also, I got the kid holding the container in the picture to drop me a "hint." He says, "The container is filled with EIGHT large $0.99 bags of jellybeans. Assuming that someone out there has bought one of these bags before, we can figure out how many jellybeans are in one bag, and from there, figure out how many are in the container. And of course, the prize is all the jellybeans. :)

I need a decent guess by as late as THURSDAY (4/17/03)!!

If you're thinking of some fancy method that involves measuring the weight: I'm not allowed to empty the container!! Perhaps there is an alternative method...? Tomorrow (the 16th), I plan on getting some measurments on the container. They have an identicle container to the one holding the jellybeans that they use to collect the guesses in, so I could measure that one.

Thanks to anyone who helps!!

I refer anyone to this great site: How many 76 antenna balls did we fit in a Chevy Trailblazer? (http://www.cockeyed.com/inside/trailblazer/trailblazer.html)

AND PLEASE: If you're going to reply to this post, please keep it constructive! There isn't much time until my guess has to be in, and I need all the time to work this out I can get!

http://atthebegining.hypermart.net/images/jelly-face.jpg
http://atthebegining.hypermart.net/images/jelly-side.jpg
http://atthebegining.hypermart.net/images/jelly-bottom.jpg

[Got_brains?]

alot! (500 ?)

[Got_brains?]

Originally posted by Infested Cats@15 April 2003 - 16:16
So, I'm sure most (if not all) of you are familiar with those "Guess how many jellybeans there are" contests. Well, I figured I could get some of you to share your educated guesses with me. With this post, I have included pictures of the FACE, SIDE, and BOTTOM of the container. Also, I got the kid holding the container in the picture to drop me a "hint." He says, "The container is filled with EIGHT large $0.99 bags of jellybeans. Assuming that someone out there has bought one of these bags before, we can figure out how many jellybeans are in one bag, and from there, figure out how many are in the container. And of course, the prize is all the jellybeans. :)

I need a decent guess by as late as THURSDAY (4/17/03)!!

If you're thinking of some fancy method that involves measuring the weight: I'm not allowed to empty the container!! Perhaps there is an alternative method...? Tomorrow (the 16th), I plan on getting some measurments on the container. They have an identicle container to the one holding the jellybeans that they use to collect the guesses in, so I could measure that one.

Thanks to anyone who helps!!

I refer anyone to this great site: How many 76 antenna balls did we fit in a Chevy Trailblazer? (http://www.cockeyed.com/inside/trailblazer/trailblazer.html)

http://atthebegining.hypermart.net/images/jelly-face.jpg
http://atthebegining.hypermart.net/images/jelly-side.jpg
http://atthebegining.hypermart.net/images/jelly-bottom.jpg
You could weigh the container then the one with the beans. subtract the container from the total,.

[Infested Cats]

Originally posted by Got_memory?@15 April 2003 - 20:58
You could weigh the container then the one with the beans. subtract the container from the total,.
Well, that would give me the weight of the Jellybeans... From there, I’d need to figure out how many jellybeans there actually are.

I need to figure out the volume of the container, and the dimensions of one jellybean.... Then just seeing how many jellybeans would fit inside of the containers volume.

But, is there a more conventional way to finding out how many jellybeans there are? Besides counting or just flat our guessing?
I say "no" to guessing because I want to guarantee that I’ll win this thing!

[Darth Sushi]

1300

[Infested Cats]

Originally posted by Darth Sushi@15 April 2003 - 21:24
1300
Any reasons you came to that conclusion?

[sArA]

800....at approx 100 per bag x 8 bags....simple but ya never know!!!

[neevakee]

are the jelly beans jelly belly brand or are they a diffrent brand. They would be marked on the bean. If so I can say theat jelly bellys go for about $6 a pound. If not I cant help you

[Darth Sushi]

Originally posted by Infested Cats+16 April 2003 - 03:27--></span><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Infested Cats @ 16 April 2003 - 03:27)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin--Darth Sushi@15 April 2003 - 21:24
1300
Any reasons you came to that conclusion? [/b][/quote]
You take the relative humidity, divided by Pi and multiply the radius of the Flux capacitor by the matter, anti-matter containment field. Square it and take the reciprocal, which equals 1300&#33; :rolleyes:

[dj7295]

you should listen to Darth Sushi, cause if you look at the front pic there is about 160 beans, look on the side and there is about 8 coloums, so 160 x 8 is 1280, which I&#39;m sure Darth Sushi is dead on cause usually in those types of contests they put in a nice round number.

[Z]

700

[Spindulik]

Byte me... ...I meant 114 X 10 =1140

[Z]

Originally posted by Spindulik@15 April 2003 - 22:11
My guess 1140&#33;

Well, there is an average of 144 jelly beans visible from the front.

There is about "10 layers" of jelly beans from the side view.

144 X 10 = 1140

To be safe, add a few extra beans. Those beans will fill in the gaps, due to settlement. So add 25 to the total.

So my second guess is 1145 :)
actually 144x10 is 1440 dumbass. :lol:

[swarnel]

a packet of jellybeans in australia has about 90 jellybeans in a &#036;2 packet. (us 99c)
but this may vary

[kAb]

Originally posted by Z+15 April 2003 - 19:22--></span><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Z @ 15 April 2003 - 19:22)</td></tr><tr><td id='QUOTE'> <!--QuoteBegin--Spindulik@15 April 2003 - 22:11
My guess 1140&#33;

Well, there is an average of 144 jelly beans visible from the front.

There is about "10 layers" of jelly beans from the side view.

144 X 10 = 1140

To be safe, add a few extra beans. Those beans will fill in the gaps, due to settlement. So add 25 to the total.

So my second guess is 1145&nbsp; :)
actually 144x10 is 1440 dumbass. :lol: [/b][/quote]
lol :lol:

honest mistake.

*must stop Zed from answering all questions in a row :w00t: *

[Z]

Originally posted by kAb+15 April 2003 - 22:23--></span><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (kAb @ 15 April 2003 - 22:23)</td></tr><tr><td id='QUOTE'>
Originally posted by -Z@15 April 2003 - 19:22
<!--QuoteBegin--Spindulik@15 April 2003 - 22:11
My guess 1140&#33;

Well, there is an average of 144 jelly beans visible from the front.

There is about "10 layers" of jelly beans from the side view.

144 X 10 = 1140

To be safe, add a few extra beans. Those beans will fill in the gaps, due to settlement. So add 25 to the total.

So my second guess is 1145 :)
actually 144x10 is 1440 dumbass. :lol:
lol :lol:

honest mistake.

*must stop Zed from answering all questions in a row :w00t: * [/b][/quote]
u no like my spam? :D

[Infested Cats]

Here&#39;s another picture:
http://www.hcrhs.k12.nj.us/info/jelly.jpg

The jar (i&#39;m pretty certain) has to contain between 1000-2000 jellybeans...

[Curley]

1450.

[Got_brains?]

Originally posted by Z+15 April 2003 - 20:25--></span><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td>QUOTE (Z @ 15 April 2003 - 20:25)</td></tr><tr><td id='QUOTE'>
Originally posted by -kAb@15 April 2003 - 22:23

Originally posted by -Z@15 April 2003 - 19:22
<!--QuoteBegin--Spindulik@15 April 2003 - 22:11
My guess 1140&#33;

Well, there is an average of 144 jelly beans visible from the front.

There is about "10 layers" of jelly beans from the side view.

144 X 10 = 1140

To be safe, add a few extra beans. Those beans will fill in the gaps, due to settlement. So add 25 to the total.

So my second guess is 1145 :)
actually 144x10 is 1440 dumbass. :lol:
lol :lol:

honest mistake.

*must stop Zed from answering all questions in a row :w00t: *
u no like my spam? :D [/b][/quote]
http://www.mansun-nl.com/smilies/finger2.gif - kidding. Funny though&#33; :lol: ;)

[merlin-1]

1550

[Infested Cats]

Originally posted by neevakee@ earlier
are the jelly beans jelly belly brand or are they a diffrent brand.&nbsp; They would be marked on the bean.&nbsp; If so I can say theat jelly bellys go for about &#036;6 a pound.&nbsp; If not I cant help you
I dont think the jellybeans are jellybelly. My school is too cheap to buy the "gormet" brand jellybeans...

Your guesses so far:
Got_memory? = 500
Darth Sushi = 1300
sara5564 = 800
dj7295 = 1280
Z = 700
Spindulik = 1140
Curley = 1450
merlin-1 = 1550

I&#39;m pretty confident with your guesses&#33; But, we should come to a final answer though&#33;

[oldmancan]

:shifty: IC this is probably too late to help. I suggest you go by the weights if you can. IF you can get an accurate container weight, big IF. The other weight you need is of one of the same brand jelly bean.

I think that production of the beans is pretty standardized, meaning all the beans will weigh the same. So if you can weigh the full container, an identical empty container and one jelly bean YOUR gonna win&#33;&#33; CHEATER&#33;&#33;

The thing about volume has been pointed out...settling. Good Luck.

[KinkoStinky]

1769

[Infested Cats]

Originally posted by oldmancan@16 April 2003 - 12:24
:shifty: IC this is probably too late to help. I suggest you go by the weights if you can. IF you can get an accurate container weight, big IF. The other weight you need is of one of the same brand jelly bean.

I think that production of the beans is pretty standardized, meaning all the beans will weigh the same. So if you can weigh the full container, an identical empty container and one jelly bean YOUR gonna win&#33;&#33; CHEATER&#33;&#33;

The thing about volume has been pointed out...settling. Good Luck.
So, what you&#39;re saying is this:

Weigh the full container of jellybeans
Weigh an identical empty container
Weigh one jellybean

But what is the math from that point?

You subtract the weight from the container, then take what&#39;s remaining, and divide it by the weight of the one jellybean.

[KinkoStinky]

Not all jelly beans weigh the same...

[Infested Cats]

Ok, 2 of my friends and I weren&#39;t allowed to weigh the container. They said it would give us an unfair advantage (because no one else thought to do it).

Anyway, we tried a different method:

First, we counted how many jellybeans were along each diaganol-side. Then we counted how many there were from the top to the bottom, and from one side to the other. Then we took the surface area from the face and then we multiplied that by how many were across.

The math may not make sense, but i&#39;ll draw a picture later.

We came up with the number 1638. It seems pretty accurate considering all of your guesses. If we stick with that number, i&#39;ll go with 1638, my one friend will go 12 more, and the other will go 12 less.

What do you think? This is due TOMORROW&#33; (4/16/03)

[KinkoStinky]

Your wronge...

[Z]

ok, take out mine and got memories guesses (700 and 500) and average the rest. then take your estimated guess and average it with the other average. then add or take away about 15 or 20, then presto&#33; :)

[Infested Cats]

Originally posted by Infested Cats@16 April 2003 - 14:27
Ok, 2 of my friends and I weren&#39;t allowed to weigh the container. They said it would give us an unfair advantage (because no one else thought to do it).

Anyway, we tried a different method:

First, we counted how many jellybeans were along each diaganol-side. Then we counted how many there were from the top to the bottom, and from one side to the other. Then we took the surface area from the face and then we multiplied that by how many were across.

The math may not make sense, but i&#39;ll draw a picture later.

We came up with the number 1638. It seems pretty accurate considering all of your guesses. If we stick with that number, i&#39;ll go with 1638, my one friend will go 12 more, and the other will go 12 less.

What do you think? This is due TOMORROW&#33; (4/16/03)
Me and my friends forgot to average in the amount of jellybeans that are between the lid and the rest of the container.

After finding the area of the area of the circle lid, we assumed about 50 more jellybeans were up in the "lid-area."

So, me and my friend&#39;s final number comes to about 1688. We&#39;re still going to do about 12 up (1700) and 12 down (1676).

[oldmancan]

:lol: IC were you suprised that you weren&#39;t allowed to weigh the container? lmao :P
Ya, you got the math, I knew you would. And your math seems reasonable so far as the latest method.
I know you haven&#39;t time but the best volume method would be to calculate the capacity (volume) of the container using Simpson&#39;s Rule. Something for you to search for. I think you want Simpsons 2nd rule. Have fun with that&#33;&#33;

King Yoshi> I suggest that the jelly beans from one production batch will be the same weight (on average) at least close enough for IC&#39;s purpose. ;)

[KinkoStinky]

I already said the amount... Anways, if you want to know, ask if you can take the beans out and then count the beans. Then after you do that, ask if you can take the Jellybeans out and then notice that you were a dumbass and counted beans... Wait, that wouldn&#39;t work... Well, your screwed...

[Bender]

Originally posted by Infested Cats@16 April 2003 - 21:27
Ok, 2 of my friends and I weren&#39;t allowed to weigh the container. They said it would give us an unfair advantage (because no one else thought to do it).

Anyway, we tried a different method:

First, we counted how many jellybeans were along each diaganol-side. Then we counted how many there were from the top to the bottom, and from one side to the other. Then we took the surface area from the face and then we multiplied that by how many were across.

The math may not make sense, but i&#39;ll draw a picture later.

We came up with the number 1638. It seems pretty accurate considering all of your guesses. If we stick with that number, i&#39;ll go with 1638, my one friend will go 12 more, and the other will go 12 less.

What do you think? This is due TOMORROW&#33; (4/16/03)
I think this is the closest you can get. :)

You should consider breaking and entering tonight though. :lol:

[KinkoStinky]

If you win, what do you win?

[Infested Cats]

Originally posted by oldmancan@16 April 2003 - 16:12
:lol: IC were you suprised that you weren&#39;t allowed to weigh the container? lmao :P
Ya, you got the math, I knew you would.&nbsp; And your math seems reasonable so far as the latest method.
I know you haven&#39;t time but the best volume method would be to calculate the capacity (volume) of the container using Simpson&#39;s Rule.&nbsp; Something for you to search for.&nbsp; I think you want Simpsons 2nd rule.&nbsp; Have fun with that&#33;&#33;
We thought at first that they would let us weight the container because we figured they&#39;d think we were "creative&#33;" :P

The only reason why i consider the math a little shady, is because we used "jellybeans" as the unit of measure. And since they&#39;re not evenly spaced, it&#39;s really not entirely accurate. Plus, not every jellybean is the same size&#33;

Also, I did a quick search on the internet concerning "Simpson&#39;s Law," and anything concerning it is WAY above my head. If you have the time oldmancan, could you perhaps explain it a little?

[ghost944]

Another thing to do is run out and buy two bags of £0.99 jellybeans count how many is in each bag, find out the average, which will give you the average of 1 bag then times it by how many bags the lad said was in the jar, that should give you near enough the right number, but the people who were counting the sweets might be dumb and counted wrong and/or they put as many as they could in their mouths then started counting from their.
D

[Infested Cats]

Originally posted by ghost944@16 April 2003 - 16:34
Another thing to do is run out and buy two bags of £0.99 jellybeans count how many is in each bag, find out the average, which will give you the average of 1 bag then times it by how many bags the lad said was in the jar, that should give you near enough the right number, but the people who were counting the sweets might be dumb and counted wrong and/or they put as many as they could in their mouths then started counting from their.
D
I could do that, but I want to win this contest without spending any money whatsoever&#33;


Also, if the number my friends and I came up with is (hopefully) accurate, then that would mean that each of the eight bags that were supposedly used contained 211 jellybeans per bag.

[oldmancan]

IC Do you have any idea how slow I type? But ok. Just don&#39;t expect anything soon. Send me a pm or just post the dimensions of the container and the size of an average jelly bean.

Oldmancan pledges to attempt to venture into areas of brain that have not seen any usage in several decades. Rusty parts beware. >Bender got any spare penetrating oil?

IC can I just answer or do I have to show my work?

btw I see I was wrong about the uniform size/weight of a jelly bean.

[Infested Cats]

I&#39;d be glad to give you the dimensions of the container&#33;... just, I havent taken measurements of the container.

I&#39;m assuming that its about 12" high, 12" or 14" across, about 6" inches per "diagonal side," and perhaps 6" for the lenght of the container?

And i have no idea about the jellybean. circumpherance is about an inch? heigh is about half and inch, and width is about an 1/8 of an inch?

It&#39;s pretty hard to just guess. Since i&#39;m home now, its a tad hard to get the dimensions. I could get the dimensions early tomorrow, and find a computer to get on to let you know.

And no, you dont have to post all the work. Just the answer if possible&#33; Thanks for all your help oldmancan&#33; The name says it all&#33; :lol:

[Infested Cats]

Just bumping this up one last time for final opinions. I need to have my guess in by 11:05am EST (4/17/03)&#33;

[Infested Cats]

My 2 friends and I put in our three guesses: 1676, 1688, and 1700.

Hopefully we won&#33;&#33; I&#39;ll let you all know.

[KinkoStinky]

When do you get to find out&#33;?&#33;

[Infested Cats]

Despite all my hard work... I didn&#39;t win the jellybeans. I didn&#39;t even get 2nd place&#33;
As it turns out, the right number of jellybeans was 1903. My highest guess (1700) was off by 203.

Of everyone on the forum that guessed, the closest person was KingYoshi with 1769, only off by 134.
I forget what the winners in my school guessed, but they guessed within the 1900&#39;s.

With 1903 as the right amount of jellybeans, if they used 8 bags to fill up the container, that means that there would be about 237.875 jellybeans per bag.

I guess I was overly confident this time.

I want to thank everyone who helped out. I DID come close, at least.

[KinkoStinky]

:(

[Bender]

Originally posted by Infested Cats@17 April 2003 - 21:01
Despite all my hard work... I didn&#39;t win the jellybeans. I didn&#39;t even get 2nd place&#33;
As it turns out, the right number of jellybeans was 1903. My highest guess (1700) was off by 203.

Of everyone on the forum that guessed, the closest person was KingYoshi with 1769, only off by 134.
I forget what the winners in my school guessed, but they guessed within the 1900&#39;s.

With 1903 as the right amount of jellybeans, if they used 8 bags to fill up the container, that means that there would be about 237.875 jellybeans per bag.

I guess I was overly confident this time.

I want to thank everyone who helped out. I DID come close, at least.
We learned a lot, next time we&#39;ll do better&#33; :D