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Peter North
11-17-2007, 04:22 PM
I dont know, but this makes me remeber of Skizo...

http://www.fukung.net/images/5494/randomness_023_2.jpg

WarrenBuffet
11-17-2007, 04:32 PM
Ha Ha Ha Rofl.

Skweeky
11-17-2007, 04:34 PM
$25???

That's peanuts.

It's like £30 if you get a fine here ( about $60)

tesco
11-17-2007, 04:48 PM
lol, cheques in texas have the longhorn thingys on them.

edit: lol, everything in texas has the longhorn thingys on them

Skweeky
11-17-2007, 04:50 PM
So when a new baby is born, do they brand it? Like cows?

tesco
11-17-2007, 04:52 PM
So when a new baby is born, do they brand it? Like cows?
probably

Something Else
11-17-2007, 06:16 PM
I dont know, but this makes me remeber of Skizo...


That makes no sense :01:

Jiggles
11-17-2007, 06:20 PM
^ it could be that Skizo has that exact longhorn pic on his avatar, could be.

Something Else
11-17-2007, 07:35 PM
''remeber of skizo'' :lol: that sounds dirty.

Jiggles
11-17-2007, 08:10 PM
^ lol at posh bittard.

pro267
11-17-2007, 10:15 PM
Ami I the only one that actually calculated it? :lol:
P.S.: I do believe he has left a 1000$+ tip for the state of Texas..

WarrenBuffet
11-17-2007, 10:52 PM
Ami I the only one that actually calculated it? :lol:
P.S.: I do believe he has left a 1000$+ tip for the state of Texas..

were you educated in the projects? It comes out to an even 25 plain and simple.

weenden
11-17-2007, 11:35 PM
rut ro skizos writin tickets i better hide

pro267
11-18-2007, 08:41 PM
Ami I the only one that actually calculated it? :lol:
P.S.: I do believe he has left a 1000$+ tip for the state of Texas..

were you educated in the projects? It comes out to an even 25 plain and simple.
Let me check again:

First I'll take the 7 out of the sigma. Now the sigma is running from n=1 to infinity with n-1 as the exponent, which is like a sigma running from n=0 to infinity with an exponent of n. For a sigma running to infinity from n=0, the formula is 1/(1-q), for |q| < 1. Therefore:

Sigma((0.8)^n) = 1/(1-0.8) = 1/0.2 = 5
==> 7*Sigma((0.8)^n) = 7*5 = 35

13.574 + (2*(e^(2*pi))) =~ 13.574 + 2*2.71^(6.28) = 1084.55731

==> 13.574 + (2*(e^(2*pi))) - 7*Sigma((0.8)^n) = 1084.55731 - 35 = 1049.55731 <> 25

Well, enough geekness for one day? :lol: