math question

[100%]

what is the size of "?"

need to cut some wood.


http://b.imagehost.org/0145/DSCF5523.jpg

& how do you calculate it?

[JPaul]

Make a triangle

34 x 5 x N

Calculate N

Done

[JPaul]

Or a measuring tape, that would work as well.

[Barbarossa]

Make a right-angled triangle at either end.

(80-70)/2 = 5.

Use Pythagoras Theorem.

34 squared = 5 squared + X squared

1156 -25 = X squared

X = square root of 1131

X = 33.63 cm

[chalice]

On the subject of maths, like, what is the next number in the below sequence and why?

32, 1312, 11131112

It's bugging the fuck out of me.

[apextwin146]

11111131111112 :unsure: [(n-1) number of ones between 3 & 2]

[Barbarossa]

On the subject of maths, like, what is the next number in the below sequence and why?

32, 1312, 11131112

It's bugging the fuck out of me.

31133112. Fact.

each number is a description of the previous number.

[chalice]

11111131111112 :unsure: [(n-1) number of ones between 3 & 2]

Nope.

I googled it and got the answer. Still don't understand it though. :blink:

I won't post the answer. I'll leave it for a while to see if some number freak gets it.

[chalice]

On the subject of maths, like, what is the next number in the below sequence and why?

32, 1312, 11131112

It's bugging the fuck out of me.

31133112. Fact.

Correct Barbs, you fucking savant you.

Why but?

[Barbarossa]

Sorry, I just ninja-added the reason in the spoiler above :smartass:

[chalice]

Nice one Barbs. I wouldn't have got that in 2 brazillion years.

Apparently it's a 'Conway Sequence'.


Where one number describes the previous number. Basically to get the next number in a sequence, look at the last number, then group all the digits in repeating groups.

For example:
Take the number: 1111333211233311222

Group it as follows:
(1111) (333) (2) (11) (2) (333) (11) (222)

Now count the number of times each digit appears in each group.
(1111) has 4 ones
(333) has 3 threes
(2) has 1 two
(11) has 2 ones
(2) has 1 two
(333) has 3 three
(11) has 2 ones
and
(222) has 3 two

or:
(4 ones) (3 threes) (1 two) (2 ones) (1 two) (3 three) (2 one) (3 twos)
which can be:
(4 1) (3 3) (1 2) (2 1) (1 2) (3 3) (2 1) (3 2)
Now write all the digits as one number:
4133122112332132

Hence, if the sequence started with 1111333211233311222, the next number is:
4133122112332132, Which would be followed by: 141123112221122312111312, and then 11142112132132212213111231131112 and so on

Ok, that's a complicated example, so lets apply this to the test sequences you asked about:
11 21 1211

Take the first number, and group common digits.
(11)

Now count the digits in each group:
(2 ones)

Now rewrite as a single number:
21.... check

repeat:
(2) (1)
(1 two) (1 one)
1211 check.

Now for the answer to the test:
(1) (2) (11)
(1 one) (1 two) (2 ones)

And the answer becomes:
111221


:blink: Still no fucking clue. Fact.

[Barbarossa]

It's just one of those things you pick up if you do a few "mensa" style tests and that.

See IQ tests are basically bullshit, you can "learn" how to do them if you practise enough

[100%]

thanks guys.
now i remember.:pinch:

[Something Else]

Have youse ever tried any of that Vedic maths. :unsure:

http://www.hinduism.co.za/vedic.htm

I tried some when I was drunk at a party. I got a terrible hangover the next day. Coincidence. I think not.

The beauty of it lies in it's simplicity.

http://www.hinduism.co.za/vedic.htm#Vedic%20Maths%20-%20Tips%20&%20Tricks

[chalice]

I got it on the new Dharma test site thing.

http://www.dharmawantsyou.com/site/index.php#/home

Try some of the tests, Barbs. You'd kick arse all over the place. There are embedded cheats and stuff. It's kewl. True story.

[Barbarossa]

I totally flunked test 2 :emo:

[apextwin146]

Nice one Barbs. I wouldn't have got that in 2 brazillion years.

Apparently it's a 'Conway Sequence'.




:blink: Still no fucking clue. Fact.
Got it .. i hope there arnt these type of questions in GMAT otherwise i am done for

[apextwin146]

Have youse ever tried any of that Vedic maths. :unsure:

http://www.hinduism.co.za/vedic.htm

I tried some when I was drunk at a party. I got a terrible hangover the next day. Coincidence. I think not.

The beauty of it lies in it's simplicity.

http://www.hinduism.co.za/vedic.htm#Vedic%20Maths%20-%20Tips%20&%20Tricks
In india there are these management exmas that utilise this .. they give u like some 70 questions to solve in 40 mins or so .. the faster you calculate , more time you get for solving the remaining questions

[Skweeky]

Have youse ever tried any of that Vedic maths. :unsure:

http://www.hinduism.co.za/vedic.htm

I tried some when I was drunk at a party. I got a terrible hangover the next day. Coincidence. I think not.

The beauty of it lies in it's simplicity.

http://www.hinduism.co.za/vedic.htm#Vedic%20Maths%20-%20Tips%20&%20Tricks


Does not everyone do maths that way? :unsure:

Or is this the reason why I'm pretty good at head calculations? No one else except the Indians have figured it out? :blink:

[JPaul]

http://www.fotos.org/galeria/data/502/3Jenna-Elfman.jpg

[clocker]

http://www.fotos.org/galeria/data/502/3Jenna-Elfman.jpg
The answer is "TWO".

[IdolEyes787]

I think some comment on root is appropriate now.

[JPaul]

I will happily put the words "root" and "Dharma" in the same sentence. You only need to ask.

[JPaul]

http://my.opera.com/Hollywoodblows/homes/blog/Jenna%20Elfman%20in%20Allure.jpg

[clocker]

http://my.opera.com/Hollywoodblows/homes/blog/Jenna%20Elfman%20in%20Allure.jpg
The answer is...assuming two trains left the station at the same time- she'd pull 'em both.

[JPaul]

Wahey!!!

[blackbird]

Nice one Barbs. I wouldn't have got that in 2 brazillion years.

Apparently it's a 'Conway Sequence'.


Where one number describes the previous number. Basically to get the next number in a sequence, look at the last number, then group all the digits in repeating groups.

For example:
Take the number: 1111333211233311222

Group it as follows:
(1111) (333) (2) (11) (2) (333) (11) (222)

Now count the number of times each digit appears in each group.
(1111) has 4 ones
(333) has 3 threes
(2) has 1 two
(11) has 2 ones
(2) has 1 two
(333) has 3 three
(11) has 2 ones
and
(222) has 3 two

or:
(4 ones) (3 threes) (1 two) (2 ones) (1 two) (3 three) (2 one) (3 twos)
which can be:
(4 1) (3 3) (1 2) (2 1) (1 2) (3 3) (2 1) (3 2)
Now write all the digits as one number:
4133122112332132

Hence, if the sequence started with 1111333211233311222, the next number is:
4133122112332132, Which would be followed by: 141123112221122312111312, and then 11142112132132212213111231131112 and so on

Ok, that's a complicated example, so lets apply this to the test sequences you asked about:
11 21 1211

Take the first number, and group common digits.
(11)

Now count the digits in each group:
(2 ones)

Now rewrite as a single number:
21.... check

repeat:
(2) (1)
(1 two) (1 one)
1211 check.

Now for the answer to the test:
(1) (2) (11)
(1 one) (1 two) (2 ones)

And the answer becomes:
111221
:blink: Still no fucking clue. Fact.

:unsure:

+1

[C-mos]

lol..that table is twisting my mind :O

[JPaul]

Oh ffs

2
12
1112
3112

[chalice]

Oh ffs

2
12
1112
3112

132112
1113122112
311311222112
13211321322112

Fuck, I'm bored.

[tralalala]

So you got it in the end chalice? :) I actually went through that site you posted.. Some wicked stuff in there.. Couldn't be arsed to sign up though so just did all the guest shite.. Managed to burn about a half an hour :01: :win:

[chalice]

So you got it in the end chalice? :) I actually went through that site you posted.. Some wicked stuff in there.. Couldn't be arsed to sign up though so just did all the guest shite.. Managed to burn about a half an hour :01: :win:

Yep, it was a slippery bastard for a while but I finally got me head around it.

That site is part of the current Lost Alternate Reality Game. It gives us Lost freaks something to do during the hiatus.

Frustrating as fuck actually. They've been putting up one test a week for the past 6 weeks. Slow-arse motherfuckers.

[tralalala]

What about Prison Break freaks..? :unsure:

[apextwin146]

What about Prison Break freaks..? :unsure:
Every week there is a competition where you have to suggest insanely stupid ways to get into prison and how to complicate the matters further while ur in there .. They make a new season out of the best one from the lot ..

[tralalala]

Only missing the fact that only 2 of the 4 seasons were actually IN prison <_<

[apextwin146]

in the other two they were trying to get into them

[tralalala]

No they weren't, they were trying to stay out. Fact.

[Jiggles]

I got it on the new Dharma test site thing.

http://www.dharmawantsyou.com/site/index.php#/home

Try some of the tests, Jiggles. You'd kick arse all over the place. There are embedded cheats and stuff. It's kewl. True story.

there was a question " what is the answer to this question?" then the options were something like A.B B.D C.A D.C , how do you work that out? do you find a pattern of As Bs Cs Ds of like the answers you got from the previous 9 or what? :huh:

[chalice]

I got it on the new Dharma test site thing.

http://www.dharmawantsyou.com/site/index.php#/home

Try some of the tests, Jiggles. You'd kick arse all over the place. There are embedded cheats and stuff. It's kewl. True story.

there was a question " what is the answer to this question?" then the options were something like A.B B.D C.A D.C , how do you work that out? do you find a pattern of As Bs Cs Ds of like the answers you got from the previous 9 or what? :huh:

Nope, that's where the cheats come in.

You'll notice on the intro page to each test, they give you a convoluted spiel about the purpose of the particular test. There are clues in them on how to cheat.

If I remember correctly, when you're asked 'What is the answer to this question', if you click on one of the 'i's on the page, the answer will flash.

Or something.

You'll find most of the answers on this site...

http://forum.lostpedia.com/forumdisplay.php?f=55

[100%]

I kicked ass at poker last night, does that mean i am in fact good at maths, and my noob question at the start is redeemed?



Although paying everyone's beer afterwards may not have been such a good idea, plus loosing my phone.

[Something Else]

Jiggles' back. :sick:

[tesco]

Only missing the fact that only 2 of the 4 seasons were actually IN prison <_<
Next year i'm sure it will be 3/5.:huh:

edit: Maybe even late this season.

They should have just made the second and future seasons a spinoff with the same characters, trying to take down 'the company'.
No need to have them in and out of prison over and over again.

[Jiggles]

Jiggles' back. :sick:

Piss off Benchez, and oh i thought you put me on your ignore list.

[Alien5]

what are you doing back again you old cunt?

[Jiggles]

what are you doing back again you old cunt?

I came back to trade some invites n shit.

[JPaul]

In the Lounge, that's against the rules.

[Proper Bo]

I've got loiyke a brazillion invites i'll never use, i would offer them to chaps here in the lounge but i'd get banned or something. It's a bit silly really.