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View Full Version : yes, another What.cd question...



LARgirl
03-21-2010, 03:33 PM
Hello all,
Let me preface this by saying I'm not an expert in the slightest when it comes to any of the topics addressed in this forum. I'm simply a person who was invited to join what.cd a year ago and has been loving and appreciating being able to download (probably not the proper term?) an album every once in a while. I was much more of a casual user I guess, only getting a few songs here or there. My ratio was fine and I had no problems. I last got some music a week ago.

Despite that, I've apparently been banned from the site for either inactivity or breaking the rules. I've neither been inactive, nor have I broken any rules. I guess this is the same claim that most banned what.cd users have, but what can you do.

My question is, I know I'm supposed to go to http://irc.what-network.net/ and then join #whatnet on a port. From what I gathered next, I'm supposed to somehow talk to a what.cd administrator (and I hear they're mean and stubborn?) and try to get my account back.

I have no idea how to do any of that. What's a port? I found some instructions in an older thread in this forum:

http://filesharingtalk.com/vb3/f-bittorrent-43/t-i-lost-my-whatcd-account-for-inactivity--354747

But I guess I need even more basic instructions because to me, the steps detailed in that post seemed to be missing parts.

So if anyone can help me, I'd sure appreciate it. I realize I've probably written way too much and everyone's most likely rolling their eyes at me, but I just wanted to be thorough in this post. Thanks so much for any help!

:)

anon
03-21-2010, 04:11 PM
The details are as follows:

irc.what.cd
#what.cd-disabled

If you're not familiar with IRC:
http://www.magic-league.com/guide/mirc.php

Tv Controls you
03-21-2010, 09:17 PM
https://addons.mozilla.org/en-US/firefox/addon/16

Install then go to tools and click chatzilla.

What to type in chatzilla:
1) /server irc.what-network.net
2) /join #what.cd-disabled

Then your in there lol.