Re: omg help! chemistry help!!11
hey man, the first one you did was wrong sorry. the equation is:
NaOH + H3PO4 -> NaH2PO4 + H20
now using the details of H3PO4
conc: 0.2 0.22
vol: 250/1000
moles: =0.22*(250/1000) (therefore, as its a 1:1 reaction, theres the same number of moles of NaOH)
now to work out the volume, you use the equation volume = moles/volume
so [0.22*(250/1000)] 0.2
will give you 0.275dm^-3, then just multiply by 1000 to get the answer in cm^-3
hope thats any help, i think its right. do you want the others done? they follow the same kinda pattern, but they seem slightly easier. well question 2 does.
Re: omg help! chemistry help!!11
fuck you all, especially manker :D
Re: omg help! chemistry help!!11
the answer to the next question (with the part a) and b) ) is:
a : 0.015 M
b: 0.09 M
again, these are the answers im getting just. if you want the working out just ask.
Re: omg help! chemistry help!!11
Quote:
Originally Posted by cpt_azad
fuck you all, especially manker :D
Break his arm with a punch captain asda.
It's the only sensible coarse.
Re: omg help! chemistry help!!11
Quote:
Originally Posted by cpt_azad
fuck you all, especially manker :D
Even the ones who tried to help.
See, this is why my arse evaluation wasn't contradicted.
Re: omg help! chemistry help!!11
Quote:
Originally Posted by manker
Quote:
Originally Posted by cpt_azad
fuck you all, especially manker :D
Even the ones who tried to help.
Even the wrong ones :blink:
Re: omg help! chemistry help!!11
Quote:
Originally Posted by JPaul
Quote:
Originally Posted by manker
Even the ones who tried to help.
Even the wrong ones :blink:
:unsure:
Re: omg help! chemistry help!!11
All i would do would pour measured amounts of a neutraliser to the solution, then test the pH with a universal indicator then rite down the amount that was used on a table 4 even more quantafiable results use a colouromiter
Re: omg help! chemistry help!!11
Quote:
Originally Posted by loadedet
All i would do would pour measured amounts of a neutraliser to the solution, then test the pH with a universal indicator then rite down the amount that was used on a table 4 even more quantafiable results use a colouromiter
Are you not better off just usinig a continuum tramfunctioner. :unsure:
Re: omg help! chemistry help!!11
Quote:
Originally Posted by exo_body
hey man, the first one you did was wrong sorry. the equation is:
NaOH + H3PO4 -> NaH2PO4 + H20
now using the details of H3PO4
conc: 0.2 0.22
vol: 250/1000
moles: =0.22*(250/1000) (therefore, as its a 1:1 reaction, theres the same number of moles of NaOH)
now to work out the volume, you use the equation volume = moles/volume
so [0.22*(250/1000)] 0.2
will give you 0.275dm^-3, then just multiply by 1000 to get the answer in cm^-3
hope thats any help, i think its right. do you want the others done? they follow the same kinda pattern, but they seem slightly easier. well question 2 does.
thanks dude, i took my test today and i figured it out, i didnt' realize someone actually posted the answer, once again thanks for taking the time to help a guy out i owe you one. at least theres some good ppl in this forum.
@manker, jesus man just STFU will ya?