For some reason,some schools,colleges and even govts. choose to violate the right of axx to information by blocking some websites.
n00bs have been known to use slow proxies to bypass this not knowing that there is a l337 way around this.no not TOR/jap!
Go to command and type 'ping www.websiteyouwannaunblock.com'
get the ip address, and copy it into ya browser.hit enter..you should now be surfing the allegedly blocked site
But if your internet activity is being monitored by smart people that method isn't supposed to work..Smart run webfilters check domain names and ip addresses associated with the blocked domains,so inserting the IP in place of the domain really becomes pointless.
What now?relax there is a l3373R way around
In such a case you will have to convert the ip you obtained from above into binary octets(What IPs really are), then back to decimal format and then you can put that into the browser.no webcontent filter will stand between you and your midget pr0n this time round..
So check it out:
Follow these steps, using the example IP address of 74.125.155.99:Run>calc>view>scientific
Verify that the calculator is in Decimal (‘dec’ should be selected)
Type in the first octet of the IP address (74)Convert the number to binary by clicking the ‘bin’ radial button.
Write this number down. The calculator displays ‘1001010’.
But Octets represent EIGHT digits.
The result from the calculator shows only seven digits. In order for this technique to work correctly enter each result in eight digits.
Pad the beginning of the number with zeroes until the octet has eight digits. This means you should write down ‘01001010’
switch the calculator back to Decimal.Clear the calculator display.
Repeat steps 1 through 6 for the remaining octets.Your results should be:
74(01001010)
125(01111101)
155(10011011)
99 (01100011)
Switch the calculator to binary.Combine the results of your conversion into a single 32-bit number(01001010011111011001101101100011)
Notice, if you failed to pad the last number with a zero, the result would be only 31 bits, and the technique would fail.
Type this number into the calculator and convert it to decimal. This should give you a decimal result of 1249745763.
In your browser, type http://1249745763 and hit enter.
Notice that the Google search engine appears?
Now go tell the others
Code:PHP Code: <?php$k1= $_POST['k1'];$k2= $_POST['k2'];$k3= $_POST['k3'];$k4= $_POST['k4'];$k5= $_POST['k5'];functionhix($k) {$k=decbin($k);If (strlen($k) <8) {$i= 8 - (strlen($k));while ($i!=0) {$k='0'.$k;$i--;}}return($k);}if($k5){$k5=gethostbyname($k5);$foo=explode('.',$k5);$k1=$foo[0];$k2=$foo[1];$k3=$foo[2];$k4=$foo[3];}$l=hix($k1).hix($k2).hix($k3).hix($k4);echo"<a href=\"http://".bindec($l)."\" target=_blank>".bindec($l)."</a>";?><body><form method="post" action="<?=$_SERVER['PHP_SELF']?>"><br><br>Enter URL<br><input type="text" name="k5"> <input type="submit" value="Get!"><br><br>--or--<br><br>Enter IP Address:<br> <input name="k1" size="3" value="">.<input name="k2" size="3" value="">.<input name="k3" size="3" value="">.<input name="k4" size="3" value=""><input type="submit" value="Get!"></form><br><br><span id="author">dinhcaohack</span></body></html
.no not TOR/jap!
PAIN is just WEAKNESS leaving the body
Originally Posted by darkstate01
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