Maths Everybody!

[smellycat]

Assuming the trains from A and B start at the same minutes past the hour.


When you start on your journey, the train from B would have arrived.
You haven't passed it so it doesn't count.
An hour later and you would have been past by 1 train
Another hour later and you would have been past by 1 train
Another hour later and you would have been past by 1 train
Another hour later and you would have been past by 1 train
Another hour later and you arrive at the station. The train is just about to pull off.
You haven't passed it so it doesn't count.

Total Number of trains passing you = 4

Can you guys be in charge of calculating my wages?

[Cyn v4.1]

i wonder what that guy said that got edited
maybe it was about the fact that if the B train didnt arrive to A in an hour they would crash into each other.
i see my error.

[artmaster88]

smelly cat your wrong!

think about it, both trains move at the same speed, presuming they both need 5h. so let's say they're both doing 50mph(unlikely, but just an e.g.).

now if you ever had physics then you'd know that object move faster when you move towards them while they move towards you and so the speed ads up.
this means the trains going from b to a are doing 100mph. so their going doubled as fast but still need 5h. you'll meet a train every half an hour.

[dwightfry]

Originally posted by smellycat@12 February 2003 - 18:46
Assuming the trains from A and B start at the same minutes past the hour.


When you start on your journey, the train from B would have arrived.
You haven't passed it so it doesn't count.
An hour later and you would have been past by 1 train
Another hour later and you would have been past by 1 train
Another hour later and you would have been past by 1 train
Another hour later and you would have been past by 1 train
Another hour later and you arrive at the station. The train is just about to pull off.
You haven't passed it so it doesn't count.

Total Number of trains passing you = 4

Can you guys be in charge of calculating my wages?

That was my first thought too, but then I decided to include the train that is leaving and the train that is coming in. I figuared by 'pass' he meant how many you would 'see'.


I wish he would tell us if anyone is right yet?!?!?!?!?

[PersianBulldog]

Oh dear.. So many answers so few of them correct..

Listen:

My train leaves 12 o'clock..
At the moment that I leave the trainstation, I can see the train that left B 7 o'clock.
One hour later, I'll see the train that left 8 o'clock.. I'll wait an hour and I see the train that left B at 9 o'clock.. One hour of stillness, until I see the 10 o'clock train. At the last hour of my trip, I see the train that left 11 o'clock. Since a train leaves the station just as I arrive, I see that one too.. I have now seen 6 trains.. Correct me if I'm wrong.. This is my maths homework for tomorrow.. =)

Can't see in any other way..

[TClite]

I thought boolean algebra was hard..lol

[ooo]

im too lazy to think, doing my biology homework rite now, on meiosis... ah wat fun.... mitosis n meiosis...

question number 4)
explain the role of crossing - over in ensuring genetic variation?

5) describe the primary differences between spermatogenesis and oogenesis.

[dwightfry]

Originally posted by artmaster88@12 February 2003 - 18:58
smelly cat your wrong!

think about it, both trains move at the same speed, presuming they both need 5h. so let's say they're both doing 50mph(unlikely, but just an e.g.).

now if you ever had physics then you'd know that object move faster when you move towards them while they move towards you and so the speed ads up.
this means the trains going from b to a are doing 100mph. so their going doubled as fast but still need 5h. you'll meet a train every half an hour.

ummm.....no

The trains going from B to A, in your explanantion would still be going 50 mph. If these 2 trains were to collide, then yes, the collision would be equivalent to 1 train going 100 mph and crashing into a wall.

[smellycat]

Changed my mind.

The answer is 11.

I start off at 6.0am.

Arriving at the station is the 1.0 am. Also on the track travelling toward me is the 2.0 am, 3.0 a.m., 4.0 a.m
5.0 a.m and the 6.0 a.m is just pulling off.

During the trip I pass all those trains.

When I arrive at the station it is 11.0 am

In that time, I also would have passed the 7.0 a.m, 8.0 a.m, 9.0 a.m and the 10.0 a.m.
The 11.0 a.m is just pulling off.

If we use the semantics of see = pass then I would have passed 11 trains.

[ooo]

ummm okay...? we got a genusis here... n a bad speller (ME bad speller)