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Thread: Maths Everybody!

  1. #21
    zdog
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    Ok, I've read the questions and have a question that might help me figure this one out. You have stated that a train leaves station B every hour although you haven't stated how long the train leaving station B takes to reach station A. Am I to suppose that trains leaving from both stations travel at the same speed???

  2. Lounge   -   #22
    If the journey takes 5 hours Then no matter how hard you try to
    make it hard, the fact is that you will pass 5 trains (and you will pass
    each one every hour no matter how fast you are travelling)

    Unless the trains coming the other way are on the same track,
    in which case you will see only one

  3. Lounge   -   #23
    dwightfry's Avatar Poster
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    Originally posted by Soul814@12 February 2003 - 23:14
    ummm okay...? we got a genusis here... n a bad speller (ME bad speller)
    actually, we all act smart, but smelly cat is the only one that got it right I think.
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  4. Lounge   -   #24
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    A1 leaves 6:00 arrives 11:00 at B

    B1 leaves 1:01 arrives 6:01 at A
    B2 leaves 2:01
    B3 leaves 3:01
    B4 leaves 4:01
    B5 leaves 5:01
    B6 leaves 6:01
    B7 leaves 7:01
    B8 leaves 8:01
    B9 leaves 9:01
    B10 leaves 10:01
    B11 leaves 11:01

    So A1 will see B1-B10

  5. Lounge   -   #25
    dwightfry's Avatar Poster
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    That's assuming that train b1 leaves at 1:01. If it leaves at exactly 1:00 then the answer would be either:

    9 = you don't count the train that has stopped right when you started and the one that starts when you stop

    or

    11 = you do count them


    I only bring this up because questions like these usually are assumed to have the trains leave at the same time.

    depending on the actual wording of the problem, 9, 10, or 11 could be right.
    Life should come with backround music
    -Dwight Fry-
    Coconut, the desert's onion
    -Dwight Fry-
    Why stand when you can lean, why lean when you can sit, why sit when you can lounge, why lounge when you can lie
    -Dwight Fry-
    www.BrownSugarStudios.com

  6. Lounge   -   #26
    Originally posted by Paul@12 February 2003 - 23:31
    A1 leaves 6:00 arrives 11:00 at B

    B1 leaves 1:01 arrives 6:01 at A
    B2 leaves 2:01
    B3 leaves 3:01
    B4 leaves 4:01
    B5 leaves 5:01
    B6 leaves 6:01
    B7 leaves 7:01
    B8 leaves 8:01
    B9 leaves 9:01
    B10 leaves 10:01
    B11 leaves 11:01

    So A1 will see B1-B10
    That assuming that their are already trains on their way I reckon
    its just as safe to assume there not.

  7. Lounge   -   #27
    zdog
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    Blue Nose, I would have to disagree with your statement, time is a variable, the time taken to travel from one point to another depends on the speed and the distance to be traveled. for eg. if you are flying from NY to Chicago in a 747 it will take you less time compared to if you were flying in a Cesena. The distance that you are traveling doesn't change but the speed at which you are traveling results in the time taken to cover the same distance. If both trains were to be travelling at the same speed then my answer would have to be 6. There are a lot of ways to contradict my answer, for eg, the trains might not be visible,( the tracks might be far apart or ther might be some obsticle in the way that would pervent you from viewing the train on the opposite track) hence you might say that i never did pass any trains, if both trains travel on the same track then there will be a head-on collision and you will not pass any trains. Unless all the details are clearly stated there is no correct answer as one different people might make different assumptions.

  8. Lounge   -   #28
    smellycat's Avatar Egalitarian BT Rep: +3
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    If we assume it's British Rail then he'd be lucky to see 1.

    Actually, he'd be lucky to even leave.
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  9. Lounge   -   #29
    Someone mentioned physics earlier and that would be on the right track because your speed adds up...so you would see a different amount of trains depending on the speed of your train and the trains departing from the other station...my guess would be if 50 mph is the speed of both trains then you would see 20 or 25 trains.

  10. Lounge   -   #30
    smellycat's Avatar Egalitarian BT Rep: +3
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    Edit: Removed gibberish
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