1. well... its like this:

were learning about parabulas in maths... (multiplication of functions)

so, how do you draw and explaine how you solve the following parabula: (2x-4)(5x+15)?????

Rafi

2. digging into brain, duhhherrrm - i think you solve it by finding where the line crosses the x-axis, and you would do that by putting the equation into the form ax"+bx+c (" that&#39;s a superscript 2 by the way)

to draw it you need to work out where the y-intercept is, and i can&#39;t remeber how

3. 1 (2x-4)(5x+15) = 10x²-20x+30x-60
= 10x²+10x-60

2 Found my old TI-83, and you&#39;re in luck : I made a little program that&#39;ll do the rest for ya : the graph intersects the X-axis (Y=O) at x=-3 and x=2

Explaination : B²-(4AC) -> discriminant, here that would be D=2500
(-B[+/-]root(D))/(2A) => intersect points

You&#39;re welcome

4. oh hum yet another student that doesn&#39;t want to put his/ her own research time in

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