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Poster
I've been trying to do this problem but I am stuck and since your all so nice :) can someone help me prove this?
If A,B, and C are the angles of any triagle show that
sin A+ sin B + sin C= 4cosA/2 cos B/2 cos C/2
Thank you for your help.
This is what I have so far..
- (a) sin C = sin(A + B).
- (B) sin A + sin B + sin (A + B) = 2 sin ((A+B)/2) ( cos ((A-B)/2) + cos ((A+B)/2) ).
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03-07-2004, 01:37 AM
Lounge -
#2
THE GREAT
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03-07-2004, 06:30 AM
Lounge -
#3
Graph it and you'll get the answer.
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