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well... its like this:
were learning about parabulas in maths... (multiplication of functions)
so, how do you draw and explaine how you solve the following parabula: (2x-4)(5x+15)?????
thanks guys... please, i need the answer by tomorrow morning
Rafi
digging into brain, duhhherrrm - i think you solve it by finding where the line crosses the x-axis, and you would do that by putting the equation into the form ax"+bx+c (" that's a superscript 2 by the way)
to draw it you need to work out where the y-intercept is, and i can't remeber how :(
1 (2x-4)(5x+15) = 10x²-20x+30x-60
= 10x²+10x-60
2 Found my old TI-83, and you're in luck : I made a little program that'll do the rest for ya : the graph intersects the X-axis (Y=O) at x=-3 and x=2
Explaination : B²-(4AC) -> discriminant, here that would be D=2500
(-B[+/-]root(D))/(2A) => intersect points
You're welcome :)
oh hum :rolleyes: yet another student that doesn't want to put his/ her own research time in :blink: